Option lowerCaseTagName: false is not respected when generating output HTML using either .toString() or .outerHTML

[jscarano]

If I use the following parse command:

        const htmlDoc = parse('<div><linkHtml href="https://nowhere.com">testing</linkHtml></div>', {
            lowerCaseTagName: false
        });

And then I use the following to get the HTML string back out:

const html = htmlDoc.toString();

the HTML string looks like the following:

testing

toString should either respect the option in the parse method, or a boolean parameter should be added to the toString() method.

e.g. const html = htmlDoc.toString(false);

[jcnventura]

The toString() method is a general Javascript method inherited from the top-level Object class. It does not support a parameter (see https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/toString).

And of course, the lowerCaseTagName option of the parse method is an option to convert all tags to lower-case when it is set to true. If it is set to false, there's no conversion happening, so you shouldn't really expect that setting it to false will be converting them to uppercase.

What you want is a new parameter called upperCaseTagName that when set to true would be converting all tags to upper-case.. Or maybe a new parameter called changeCaseTagName that would convert to lower if set to 'lower', and to upper if set to 'upper', and otherwise not converting at all if set to anything else.

[jscarano]

The issue that I am seeing is that the HTML tags are always in lowercase when outputting an HTML string. It doesn't matter that the lowerCaseTagName: false option is used. The .toString() method should not convert the tags to lowercase if the parse option is set not to.

[taoqf]

It won't.

The .toString() method should not convert the tags to lowercase if the parse option is set not to.